𝙵̷𝚘̷𝚕̷𝚕̷𝚘̷𝚠̷ 𝚝̷𝚑̷𝚎̷ 𝚠̷𝚑̷𝚒̷𝚝̷𝚎̷ 𝚛̷𝚊̷𝚋̷𝚋̷𝚒̷𝚝̷ 🐇

Using the Euler’s identity

e^{i\pi} + 1 = 0

Which is derived from Euler’s formula:

e^{ix} = \cos x + i \sin x

So, we get:

e^{i\pi} = \cos \pi + i \sin \pi = -1 + 0i = -1

Therefore:

e^{i\pi} + 1 = -1 + 1 = 0


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