OliviatenFoster pfp

OliviatenFoster

@oliviatenfoster

568 Following
301 Followers
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
Only persistence leads to results
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
Pay attention to rest
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
Thank you for sharing
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
Thank you for the reminder
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
It looks really appetizing
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
🎉 I just minted my DAO BadgeX, and I'm ranking at 0.989! 🎉 Join the fun by claiming yours, and boost your on-chain cred 🚀 👇 https://daobase.ai/point/task?inviteId=G32ZI4
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
Double-cooked squid with peppers and fermented black beans – a spicy treat! 🦑🌶️
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
Stay indoors during extreme heat: Avoid strenuous outdoor activities in extreme heat; choose indoor or water-based activities instead.
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
I got my Moxie Pass! Mint yours to be eligible for upcoming airdrops, grants, Fan Tokens and more! cc @betashop.eth @airstack.eth
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
I got my Moxie Pass! Mint yours to be eligible for upcoming airdrops, grants, Fan Tokens and more! cc @betashop.eth @airstack.eth
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
Marilyn Monroe: Monroe, an iconic Hollywood actress and model, became a symbol of beauty and glamour in the 1950s
0 reply
0 recast
0 reaction
Vitalik Buterin pfp
Vitalik Buterin
@vitalik.eth
https://x.com/AlgebraFact/status/1802110136472817917 This identity simple, but shows important fact: the norm for complex numbers is multiplicative (a+ci)*(b+di) = (ab-cd)+(ad+bc)i norm(x+yi) = sqrt(x^2+y^2) So (ab-cd)^2+(ad+bc)^2 = norm((a+ci)*(b+di)) (a^2+c^2)(b^2+d^2) = norm(a+ci)*norm(b+di) The two are equal
12 replies
189 recasts
1054 reactions
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
https://wallet.coinbase.com/nft/mint/smartwallet
0 reply
0 recast
0 reaction
OliviatenFoster pfp
OliviatenFoster
@oliviatenfoster
During a night shift in the ICU, I comforted a terminally ill patient. We reminisced about their life achievements, and they passed away peacefully knowing they were valued and cared for. It reaffirmed my commitment to compassionate end-of-life care and the importance of human connection in nursing.
0 reply
0 recast
0 reaction