liukansheng

@15813118227

150 Following

235 Followers

liukansheng pfp

看我主页有想法可以一起

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liukansheng pfp

这个号以后开始每天撸空头打卡，目的在于给大家查漏补缺，如果你也想一起参与，直接评论区留言，一起抱团取暖，打卡连续超过15天以上我拉群 3.18打卡 1.monad测试网 telentum签到肝monad生态dc 拿角色抽白 2.abs 日活剪刀石头布 3.牛顿丢骰子签到牛顿dc拿角色绑定 4.掌纹签到

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liukansheng pfp

这个号以后开始每天撸空头打卡，目的在于给大家查漏补缺，如果你也想一起参与，直接评论区留言，一起抱团取暖，打卡连续超过15天以上我拉群 3.18打卡 1.monad测试网 telentum签到肝monad生态dc 拿角色抽白 2.abs 日活剪刀石头布 3.牛顿丢骰子签到牛顿dc拿角色绑定 4.掌纹签到

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liukansheng pfp

这个群怎么进呢

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liukansheng pfp

老师，姨太的点位呢会变吗

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Jason Goldberg pfp

if you're still having any trouble claiming your Moxiedrop from this frame can you please let us know below reminder: Desktop is much more flexible than mobile for warpcast frames transactions https://warpcast.com/betashop.eth/0x97906c21

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𒂭_𒂭 pfp

we should get Robin Hanson on to Farcaster.

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liukansheng pfp

今日任务1.完成各项币安ok签到任务 2.完成tg的各种app小游戏 3.完成为威科夫阅读

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liukansheng pfp

健身计划：今日休息币圈计划： 1.完成各项每日签到，晚上停下y总的威科夫投资法 2.观看威科夫投资心法电子书 3.准备教师面试，查找有关教师优秀试讲课，理清节奏

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liukansheng pfp

暑假真的无聊有没有什么事可以做下的

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Brian Armstrong pfp

Brian Armstrong

We’re continuing to work hard on Coinbase Wallet. Lots of new features to come. If there is a top request you have, drop us a comment below. 🙏

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liukansheng pfp

https://x.com/asianiun/status/1808354486446182456?s=46&t=EdYXbPATupAs2xd4GbhX0w

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liukansheng pfp

10 Moxie Passes available — mint yours to be eligible for upcoming airdrops, grants, Fan Tokens, and more! cc @betashop.eth @airstack.eth

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Sassal.eth 🎩⛽ pfp

Sassal.eth 🎩⛽

Just wanted to say that I appreciate ya'll so much. The Daily Gwei would be nothing without the awesome community that has formed around it. Honestly so humbled by it all - thank you for your support ❤️

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liukansheng pfp

今天下午两点健身了一个小时，晚上继续学习体育心理学，好难啊😩

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liukansheng pfp

现在的想法是打算考公存本金然后实现自由

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liukansheng pfp

考公一定是出路吗？真的不想跟他们卷

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✳️ dcposch pfp

.eth urbanist crossover, very nice https://x.com/0xgaut/status/1804190372446257539

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Vitalik Buterin pfp

Vitalik Buterin

https://x.com/AlgebraFact/status/1802110136472817917 This identity simple, but shows important fact: the norm for complex numbers is multiplicative (a+ci)*(b+di) = (ab-cd)+(ad+bc)i norm(x+yi) = sqrt(x^2+y^2) So (ab-cd)^2+(ad+bc)^2 = norm((a+ci)*(b+di)) (a^2+c^2)(b^2+d^2) = norm(a+ci)*norm(b+di) The two are equal

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liukansheng pfp

https://x.com/wy_mask/status/1802881511466906000?s=46&t=EdYXbPATupAs2xd4GbhX0w每日一做

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